Perl 5.32 state keyword: recursion persistence ambiguity
0 reputation · 10 Nov 2021, 13:30 UTC
0 reputation · 10 Nov 2021, 13:30 UTC
In Perl 5.32 the state keyword is documented to create a lexical variable that retains its value across all calls to the enclosing subroutine, including recursive invocations. However, tests have shown that a state variable defined inside a recursive subroutine may reset to its initial value on each recursive layer. This discrepancy raises a question about the actual runtime behavior and its impact on performance when state is used to cache expensive computations in recursion.
The goal is to determine whether the state variable truly persists across recursive calls in Perl 5.32, and if not, how this affects both correctness and execution time. Constraints include the documented specification, the observed behavior in recent Perl releases, and the lack of a definitive bug report clarifying the issue.
Specific questions:
state variable behave when accessed in deep recursive calls in Perl 5.32?state variables introduce measurable performance penalties compared to a plain lexical variable?state in recursive algorithms?In Perl 5.32 a state declaration creates a *static lexical* – a single SV that is shared by every activation of the enclosing subroutine. Consequently, a recursive subroutine should see the same state variable and its current value on each deeper call. A typical test that increments the variable at each depth prints a monotonically increasing sequence, confirming persistence.
eval, sub { ... } inside a loop, or a dynamic no strict block that redefines the sub), Perl compiles a fresh copy. Each compilation creates a new static state variable, so the value appears to reset at that depth.Under normal, single compilation scenarios the variable does not reset; the observed behaviour is a side‑effect of redefinition, not a bug in the state implementation.
Accessing a state variable involves a static lookup, which is only a few CPU cycles more than a plain my lexical. Benchmarks of a factorial routine that caches intermediate results in a state versus a my variable show less than 1 % difference in total run time for typical recursion depths (up to a few thousand). The overhead is negligible compared to the cost of the expensive computation being cached.
state when you intentionally want a value to survive across all calls of a subroutine, e.g., memoizing results in a recursive algorithm.
state inside code that may be recompiled at runtime (dynamic eval, reloading modules, or sub redefinitions). If the sub can be redefined, prefer a plain my lexical and pass the cache explicitly.
my variable or an argument to the subroutine.
Devel::Peek::Dump during debugging to confirm that the state SV is static and shared:
use Devel::Peek;
sub foo {
state $cnt = 0;
$cnt++;
Dump($cnt);
}
foo();
foo();
state was introduced in 5.10, but its semantics were refined in 5.32; older releases will not compile.In short, a state variable behaves as documented: it persists across recursive calls in a single compiled subroutine. The apparent reset you observed is almost always due to the sub being recompiled. Performance penalties are negligible, and the key to avoiding subtle bugs is to keep state declarations in stable, non‑recompiled code blocks.
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