Does grunt.task.run inside a Grunt multi-task execute after the current target or only after all targets complete?
0 reputation · 31 Dec 2021, 09:39 UTC
0 reputation · 31 Dec 2021, 09:39 UTC
Grunt's runtime task queue lets a task enqueue additional work via grunt.task.run, but the documented API does not specify how this interacts with multi-task target boundaries. When a multi-task calls grunt.task.run from inside one target, is the enqueued task deferred until the entire multi-task finishes across all targets, or does it run after the current target completes?
The ambiguity is amplified when the multi-task uses this.async() and signals completion asynchronously, because the boundary between a single target finishing and the overall task queue advancing becomes unclear. Without explicit documentation, teams cannot tell whether the enqueued task is appended to a global queue that waits for the full multi-task lifecycle or whether it can interleave per-target.
Behavior may also differ across Grunt versions if internal queue handling changed, so practical verification against the version in use is needed. Can the execution boundary be predicted reliably for a specific Grunt version, what role does this.async() play in when the enqueued task becomes eligible, and is there any documented guarantee for ordering when dynamically enqueuing from within a multi-task target?
When a Grunt multi-task target calls grunt.task.run, the enqueued task does not execute after that individual target. It is appended to the global run queue and executes only after the entire multi-task has completed across all of its targets.
Grunt invokes a multi-task once per target, but it does not flush the task queue between those invocations. A call to grunt.task.run('someTask') inside any target adds someTask to the end of the global queue. That queued task becomes eligible only when the current task invocation signals completion: either by returning synchronously or by calling the done callback obtained from this.async(). Because the multi-task itself is not considered finished until every target has run, the enqueued task waits for the full multi-task lifecycle.
this.async()The async contract controls when the enqueued task becomes eligible. If a target calls this.async() and delays done(), the global queue does not advance until done() fires. In a synchronous target, the queue advances as soon as the target function returns. In both cases, the boundary is the completion of the current task invocation, not the completion of a single target within a multi-task.
This behavior is consistent across the Grunt 0.4.x and 0.5.x series. Releases prior to 0.4.0 used a different queue implementation, so if you are on an extremely legacy version, verify the behavior separately rather than assuming the same ordering.
Create a minimal Gruntfile to confirm the ordering:
module.exports = function(grunt) {
grunt.initConfig({});
grunt.registerTask('logAfter', function() {
grunt.log.writeln('logAfter executed');
});
grunt.registerMultiTask('demo', function() {
grunt.log.writeln('target start: ' + this.target);
grunt.task.run('logAfter');
grunt.log.writeln('target end: ' + this.target);
});
grunt.registerTask('default', ['demo:a', 'demo:b']);
};
Run grunt. The logAfter output should appear only after both demo:a and demo:b have printed their start and end lines. To test the async path, replace the multi-task body with var done = this.async(); setTimeout(done, 100); and observe that logAfter still waits until the delayed done() resolves.
Grunt provides no supported mechanism to interleave a queued task between targets of a single multi-task invocation. If your build requires work to run after each target, restructure the logic into separate tasks and invoke them explicitly, or implement a custom iterator that calls done() per target and manages its own queue.
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